
ERROR using CharIndex : Invalid length parameter passed to the LEFT …
Apr 18, 2017 · In such cases, your CHARINDEX expressions will evaluate to -1, which is an invalid length parameter to pass to the LEFT function. I think you'll need a CASE expression to handle …
CHARINDEX Not Finding String – SQLServerCentral Forums
Oct 3, 2011 · CHARINDEX Not Finding String Forum – Learn more on SQLServerCentral
String Manipulation - CHARINDEX () – SQLServerCentral
Feb 13, 2009 · String Manipulation - CHARINDEX () Seth Phelabaum, 2009-12-19 I see charindex used quite commonly in string manipulation. What I rarely see used is the optional third parameter.
Find the Nth Occurrence of a Character in a String
Aug 5, 2002 · T-SQL's CHARINDEX () function is a useful for parsing out characters within a string. However, it only returns the first occurrence of a character.
Extracting a String From Between Two Delimiting Characters
May 22, 2001 · Extracting a string from between two delimiting characters The problem A table contains a column (particulars) consisting of a semi-colon-delimited string of text, for which the text between …
Performance difference between LIKE and CHARINDEX?
Mar 8, 2013 · Based on that, the differences between LIKE and CHARINDEX are negligible with the split string and join method following close behind.
Extracting string after and before a Character/Pattern
Aug 19, 2009 · If we want to extract before the character you would put the charindex as the number of characters and start position as 0 in the substring function ----select characters before / select …
Find the second occurrence in the string - SQLServerCentral
Aug 2, 2018 · Home Forums SQL Server 2016 SQL Server 2016 - Development and T-SQL Find the second occurrence in the string Post reply
Find spaces between First and Last Name in Microsoft SQL
Jun 23, 2023 · In Microsoft SQL, you can find the spaces between the first and last name using various string manipulation functions.
Find last occurence of a character within a string
Apr 8, 2009 · Hi All, I am trying to find the last occurence of a character within a string. I have the following code: what is the easiest way to accomplish this? SELECT CASE WHEN FieldA IS NULL …